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Getting #DIV/0!, how to get 0%?

 
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kevin

External


Since: Mar 31, 2006
Posts: 23



(Msg. 25) Posted: Fri Nov 06, 2009 10:36 am
Post subject: Re: Getting #DIV/0!, how to get 0%? [Login to view extended thread Info.]
Archived from groups: microsoft>public>excel>misc (more info?)

I am still getting a Value after changing formula to instead of #DIV/0!
=IF(c13=0,0,(c12:c16)/c13

"Peo Sjoblom" wrote:

> =IF(E34=0,0,(E34-D34)/E34)
>
> --
>
>
> Regards,
>
>
> Peo Sjoblom
>
>
>
> "pgarcia" <pgarcia.TakeThisOut@discussions.microsoft.com> wrote in message
> news:F777B88C-63AF-4202-8F40-6218195C2EE1@microsoft.com...
> > I'm getting #DIV/0! with the following formula, the cell is format as a
> > percent. Thanks
> >
> > =(E34-D34)/E34
> > E34 = 0
> > D34 = 0
> > Result should be 0%
>
>
>
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Peo Sjoblom

External


Since: May 20, 2009
Posts: 16



(Msg. 26) Posted: Fri Nov 06, 2009 11:41 am
Post subject: Re: Getting #DIV/0!, how to get 0%? [Login to view extended thread Info.]
Archived from groups: per prev. post (more info?)

You are using a range divided by a number and you should change that to a
single cell

=IF(C13=0,0,C12/C13)


or something


and the only way you can get a value error is if C13 itself has a DIV error
in it.


Maybe you should explain what you are trying to do instead?

--


Regards,


Peo Sjoblom


"kevin" <kevin DeleteThis @discussions.microsoft.com> wrote in message
news:45F01960-E162-4151-9731-318C977C8C6F@microsoft.com...
>I am still getting a Value after changing formula to instead of #DIV/0!
> =IF(c13=0,0,(c12:c16)/c13
>
> "Peo Sjoblom" wrote:
>
>> =IF(E34=0,0,(E34-D34)/E34)
>>
>> --
>>
>>
>> Regards,
>>
>>
>> Peo Sjoblom
>>
>>
>>
>> "pgarcia" <pgarcia DeleteThis @discussions.microsoft.com> wrote in message
>> news:F777B88C-63AF-4202-8F40-6218195C2EE1@microsoft.com...
>> > I'm getting #DIV/0! with the following formula, the cell is format as a
>> > percent. Thanks
>> >
>> > =(E34-D34)/E34
>> > E34 = 0
>> > D34 = 0
>> > Result should be 0%
>>
>>
>>
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